The given table shows the freezing points in °F of different gases at sea level. Convert each of these into °C to the nearest integral value using the relation and complete the table, C = 5/9(F - 32)

Solution:

In the given problem we have,

C = 5/9 (F - 32).

Substituting the values for hydrogen we get,

F = -435

C = 5/9 (-435 - 32)

C = -259.44

Substituting the values for krypton we get,

F = -251

C = 5/9 (-251 - 32)

C = -157.22

Substituting the values for oxygen we get,

F = -369

C = 5/9 (-369 - 32)

C = -223

Substituting the values for helium we get,

F = -458

C = 5/9 (-458 - 32)

C = -272.22

Substituting the values for argon we get,

F = -309

C = 5/9 (-309 - 32)

C = -189.44

✦ Try This: If the freezing point at of hydrogen at sea level (°F) is -482 convert the value in °C.

To convert the value from °F to °C we will substitute the value of F in C = 5/9(F - 32) and further using properties of integers we can easily convert the freezing point.

☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 1

NCERT Exemplar Class 7 Maths Chapter 1 Exercise Problem 129

The given table shows the freezing points in °F of different gases at sea level. Convert each of these into °C to the nearest integral value using the relation and complete the table, C = 5/9(F - 32)

Summary:

After applying the integer rules we converted the following freezing point as:

Hydrogen = -259.44 °C

Krypton = -157.22 °C

Oxygen = -223 °C

Helium = -272.22 °C

Argon = -189.44 °C

☛ Related Questions:

• Sana and Fatima participated in an apple race. The race was conducted in 6 parts. In the first part, . . . .
• A green grocer had a profit of rupees 47 on Monday, a loss of rupees 12 on Tuesday and loss of rupee . . . .
• In a test, +3 marks are given for every correct answer and -1 mark are given for every incorrect ans . . . .