The given distribution shows the number of runs scored by some top batsman of the world in one-day international cricket matches
Find the mode of the data.
Solution:
Modal Class is the class with the highest frequency
Mode = l + [(f₁ - f₀) / (2f₁ - f₀ - f₂)] × h
Here,
- Class size, h
- Lower limit of modal class, l
- Frequency of modal class, f₁
- Frequency of class preceding modal class, f₀
- Frequency of class succeeding the modal class, f₂
From the table, it can be observed that the maximum class frequency is 18, belonging to class interval 4000 − 5000
Therefore, modal class = 4000 − 5000
Class size, h = 1000
Lower limit of modal class, l = 4000
Frequency of modal class, f₁ = 18
Frequency of class preceding modal class, f₀ = 4
Frequency of class succeeding the modal class, f₂ = 9
Mode = l + [(f₁ - f₀)/(2f₁ - f₀ - f₂)] × h
= 4000 + [(18 - 4)/(2 × 18 - 4 - 9)] × 1000
= 4000 + [14/(36 - 13)] × 1000
= 4000 + (14/23) × 1000
= 4000 + 608.695
= 4608.695
= 4608.7
Hence the mode is 4608.7
☛ Check: NCERT Solutions for Class 10 Maths Chapter 14
Video Solution:
The given distribution shows the number of runs scored by some top batsman of the world in one-day international cricket matches. Find the mode of the data.
NCERT Solutions for Class 10 Maths Chapter 14 Exercise 1.2 Question 5
Summary:
The mode of the given distribution showing the number of runs scored by some top batsman of the world in one-day international cricket matches is 4608.7.
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