The first four terms of an AP, whose first term is -2 and the common difference is -2, are
a. - 2, 0, 2, 4
b. - 2, 4, - 8, 16
c. - 2, - 4, - 6, - 8
d. - 2, - 4, - 8, -16
Solution:
An arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous term.
The nth term of an AP is
aₙ = a + (n - 1 )d.
a = first term
aₙ = nth term
d = common difference.
As per the given question, we have,
First term, a = -2
Second Term, d = -2
a₁ = a = - 2.
Considering the question,
aₙ = a + (n - 1 )d.
a₂ = - 2 + (- 2) = - 4
a₃ = - 2 + (3 - 1) (-2) = - 6
a₄ = -2 + (4 - 1) (-2) = - 8.
The A.P is - 2, - 4, - 6, - 8.
Therefore, the A.P is - 2, - 4, - 6, - 8.
✦ Try This: Maria considered the below AP: 7, 11, 15, 19,...How will she determine if the number 301 is a part of this AP
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 5
NCERT Exemplar Class 10 Maths Exercise 5.1 Problem 5
The first four terms of an AP, whose first term is -2 and the common difference is -2, are, a. - 2, 0, 2, 4, b. - 2, 4, - 8, 16, c. - 2, - 4, - 6, - 8, d. - 2, - 4, - 8, -16
Summary:
The first four terms of an AP, whose first term is -2 and the common difference is -2, are - 2, - 4, - 6, - 8
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