The fee charged every month by a school from Classes I to XII, when the monthly fee for Class I is Rs 250, and it increases by Rs 50 for the next higher class, do the lists of numbers involved form an AP

Solution:

An arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous term.

From the question given,

The monthly fee from I to XII is 250, (250+50), (250 + 2 × 50), (250 + 3 × 50),….

(250, 300, 350, 400,….)

Calculating the difference, we get,

d₁ = 300 - 250 = 50

d₂ = 350 - 300 = 50

d₃ = 400 - 350 = 50

Since, the d = 50 is the same for all, i.e. d₁ = d₂ = d₃. The above statement forms an AP.

Therefore a given list of numbers formed by monthly fees from I to XII forms an AP.

Therefore, it forms an A.P with a common difference 50.

✦ Try This: The 14th term of an AP is twice its gth term. If its 6th term is -8, then find the sum of its first 20 terms

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 5

NCERT Exemplar Class 10 Maths Exercise 5.2 Problem 7 (ii)

The fee charged every month by a school from Classes I to XII, when the monthly fee for Class I is Rs 250, and it increases by Rs 50 for the next higher class, do the lists of numbers involved form an AP

Summary:

The fee charged every month by a school from Classes I to XII, when the monthly fee for Class I is Rs 250, and it increases by Rs 50 for the next higher class, forms an A.P

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