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The factors of x² - 4 are
(a) (x - 2), (x - 2)
(b) (x + 2), (x - 2)
(c) (x + 2), (x + 2)
(d) (x - 4), (x - 4)

Solution:

Correct option is (b).

Given, x² - 4 = x² - (2)²

The is in the form of the standard identity a² - b² = (a + b) (a - b)

Here, a = x and b = 2

∴ x² - (2)² = (x + 2) (x - 2)

✦ Try This: Factors of p² - 64 are (a) (p - 8), (p - 8) (b) (p + 8), (p - 8) (c) (p + 8), (p + 8) (d) (p - 64), (p + 64)

Correct option is (b).

Given, p² - 64 = p² - (8)²

The is in the form of the standard identity a² - b² = (a + b) (a - b)

Here, a = p and b = 8

∴ p² - (8)² = (p + 8) (p - 8)

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 28

Summary:

The factors of x² - 4 are (x + 2) (x - 2)

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