The equation of x-axis is of the form
a. x = 0
b. y = 0
c. x + y = 0
d. x = y
Solution:
We know that
Points on the x-axis are of the form (a, 0) where a is any real number
y-coordinate of the point of x-axis is 0
y = 0 is the equation of the x-axis
Therefore, the equation of x-axis is y = 0.
✦ Try This: If (5, 0) is a solution of the linear equation 3x + 4y = 6k, then the value of k is a. 4, b. 6, c. 5/2, d. 2
The given linear equation is
3x + 4y = 6k
The point given here is
(x, y) = (5, 0)
Let us substitute the given values in the equation
3 (5) + 4(0) = 6k
By further calculation
15 + 0 = 6k
So we get
k = 15/6
k = 5/2
Therefore, the value of k is 5/2.
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 4
NCERT Exemplar Class 9 Maths Exercise 4.1 Problem 9
The equation of x-axis is of the form a. x = 0, b. y = 0, c. x + y = 0, d. x = y
Summary:
The horizontal axis in a coordinate plane is represented by the x-axis. The equation of x-axis is of the form y = 0
☛ Related Questions:
- The graph of y = 6 is a line a. parallel to x-axis at a distance 6 units from the origin, b. paralle . . . .
- x = 5, y = 2 is a solution of the linear equation a. x + 2y = 7, b. 5x + 2y = 7, c. x + y = 7, d. 5 . . . .
- If a linear equation has solutions (-2, 2), (0, 0) and (2, -2), then it is of the form a. y - x = 0, . . . .
visual curriculum