The distance between the points A (0, 6) and B (0, –2) is
a. 6
b. 8
c. 4
d. 2
Solution:
We know that the formula to find the distance between two points A(x₁, y₁) and B(x₂, y₂) is
Distance=\(\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\)
It is given that
We have to find the distance between the points A (0, 6) and B (0, –2)
Substituting these values in the equation we get
Distance = \(\sqrt{(0-0)^{2}+(-2 - 6)^{2}}\)
So we get
Distance between A and B = √64
Distance between A and B = 8 units
Therefore, the distance between the points A and B is 8 units.
✦ Try This: The distance between the points P (0, 8) and Q (0, -4) is
We know that the formula to find the distance between two points P(x₁, y₁) and Q(x₂, y₂) is
Distance = \(\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\)
It is given that
We have to find the distance between the points P (0, 8) and Q (0, -4)
Substituting these values in the equation we get
Distance = \(\sqrt{(0-0)^{2}+(-4 - 8)^{2}}\)
So we get
Distance between P and Q = √144
Distance between P and Q = 12 units
Therefore, the distance between the points P and Q is 12 units.
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 7
NCERT Exemplar Class 10 Maths Exercise 7.1 Problem 2
The distance between the points A (0, 6) and B (0, –2) is a. 6 ,b. 8, c. 4, d. 2
Summary:
The distance between the points A (0, 6) and B (0, –2) is 8 units
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