The distance between the points A (0, 6) and B (0, –2) is
a. 6
b. 8
c. 4
d. 2

Solution:

We know that the formula to find the distance between two points A(x₁, y₁) and B(x₂, y₂) is

Distance=\(\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\)

It is given that

We have to find the distance between the points A (0, 6) and B (0, –2)

Substituting these values in the equation we get

Distance = \(\sqrt{(0-0)^{2}+(-2 - 6)^{2}}\)

So we get

Distance between A and B = √64

Distance between A and B = 8 units

Therefore, the distance between the points A and B is 8 units.

✦ Try This: The distance between the points P (0, 8) and Q (0, -4) is

We know that the formula to find the distance between two points P(x₁, y₁) and Q(x₂, y₂) is

Distance = \(\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\)

It is given that

We have to find the distance between the points P (0, 8) and Q (0, -4)

Substituting these values in the equation we get

Distance = \(\sqrt{(0-0)^{2}+(-4 - 8)^{2}}\)

So we get

Distance between P and Q = √144

Distance between P and Q = 12 units

Therefore, the distance between the points P and Q is 12 units.

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 7

---

NCERT Exemplar Class 10 Maths Exercise 7.1 Problem 2

The distance between the points A (0, 6) and B (0, –2) is a. 6 ,b. 8, c. 4, d. 2

Summary:

The distance between the points A (0, 6) and B (0, –2) is 8 units

---

☛ Related Questions:

• The distance of the point P (–6, 8) from the origin is a. 8, b. 2 √7, c. 10, d. 6
• The distance between the points (0, 5) and (–5, 0) is a. 5, b. 5 √2, c. 2 √5, d. 10
• AOBC is a rectangle whose three vertices are vertices A (0, 3), O (0, 0) and B (5, 0). The length of . . . .