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The distance between the points (0, 5) and (–5, 0) is
a. 5
b. 5 √2
c. 2 √5
d. 10

Solution:

We know that the formula to find the distance between two points P(x₁, y₁) and Q(x₂, y₂) is

Distance = \(\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\)

It is given that

We have to find the distance between the points (0, 5) and (–5, 0)

Substituting these values in the equation we get

\(Distance=\sqrt{(-5-0)^{2}+(0 - 5)^{2}}\)

So we get

Distance between the points = √(25 + 25) = √50 = 5√2

Distance between the points = 5√2 units

Therefore, the distance between the points (0, 5) and (–5, 0) is 5√2 units.

✦ Try This: The distance between the points (0, 4) and (-4, 0) is

We know that the formula to find the distance between two points P(x₁, y₁) and Q(x₂, y₂) is

Distance = \(\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\)

It is given that

We have to find the distance between the points (0,4) and (-4, 0)

Substituting these values in the equation we get

Distance = \(\sqrt{(-4-0)^{2}+(0 - 4)^{2}}\)

So we get

Distance between the points = √(16 + 16) = √32 = 4√2

Distance between the points = 4√2 units

Therefore, the distance between the points (0, 4) and (-4, 0) is 4√2 units.

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 7

NCERT Exemplar Class 10 Maths Exercise 7.1 Problem 4

The distance between the points (0, 5) and (–5, 0) is a. 5, b. 5 √2, c. 2 √5, d. 10

Summary:

The distance between the points (0, 5) and (–5, 0) is 5√2 units

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