The curved surface area of a right circular cylinder of height 14 cm is 88 cm². Find the diameter of the base of the cylinder.

Solution:

Let the radius and height of the cylinder be 'r' and 'h' respectively.

Curved Surface Area of a right circular cylinder = 2 π r h

Diameter = 2 × radius

Height of the cylinder, h = 14 cm

CSA of the cylinder = 88 cm²

2 π r h = 88 cm²

2 × 22/7 × r × 14 cm = 88 cm²

r = (88 cm² × 7) / (2 × 22 × 14) cm

= 1 cm

Diameter = 2 × radius

= 2 × 1 cm

= 2 cm

Thus, the diameter of the base of the cylinder is 2 cm.

☛ Check: NCERT Solutions for Class 9 Maths Chapter 13

Video Solution:

The curved surface area of a right circular cylinder of height 14 cm is 88 cm². Find the diameter of the base of the cylinder.

Class 9 Maths NCERT Solutions Chapter 13 Exercise 13.2 Question 1

Summary:

It is given that curved surface area of a right circular cylinder of height 14 cm is 88 cm^². We have found that diameter of the base of the cylinder is 2 cm.

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