The common factor of 3ab and 2cd is
(a) 1
(b) -1
(c) a
(d) c

Solution:

Correct option is (a).

The factors of 3ab = 3 × a × b and

2cd = 2 × c × d

∴ There are no common terms, common factor can only be 1 as every number has a common factor that is one and the number itself.

✦ Try This: The common factors of -12pq and -5ab is (a) 1, (b) - 1, (c) pq, (d) ab

Correct option is (b)

The factors of -12pq = - 1 × 3 × 2 × 2 × p × q

And factors of -5ab = -1 × 5 × a × b

∴ Common factor can only be -1

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 24

The common factor of 3ab and 2cd is (a) 1, (b) - 1, (c) a, (d) c

Summary:

The common factor of 3ab and 2cd is 1

☛ Related Questions:

• An irreducible factor of 24x²y² is (a) x² (b) y² (c) x (d) 24x
• Number of factors of (a + b)² is (a) 4 (b) 3 (c) 2 (d) 1
• The factorised form of 3x - 24 is (a) 3x × 24 (b) 3 (x - 8) (c) 24 (x - 3) (d) 3(x -12)