The coach of a cricket team buys 3 bats and 6 balls for ₹ 3900. Later, she buys another bat and 3 more balls of the same kind for ₹ 1300. Represent this situation algebraically and geometrically.
Solution:
Assuming the cost of one bat as ₹ x and the cost of one ball as ₹y, two linear equations can be formed for the situation given.
The cost of 3 bats and 6 balls is ₹ 3900. Mathematically:
3x + 6y = 3900
Also, the cost of 1 bat and 3 balls is ₹ 1300. Mathematically:
x + 3y = 1300
Algebraic representation where x and y are cost of bat and ball respectively.
3x + 6y = 3900 ---(1)
x + 3y = 1300 ---(2)
Therefore, the algebraic representation for equation (1) is:
3x + 6y = 3900
⇒ y = (1300 - x) / 2
And, the algebraic representation for equation (2 )is:
x + 3y = 1300
⇒ y = (1300 - x) / 3
Let us represent these equations graphically. For this, we need at least two solutions for each equation. We give these solutions in table shown below.
|
x |
500 |
900 |
|
y |
400 |
200 |
|
x |
400 |
700 |
|
y |
300 |
200 |
The graphical representation is as follows.
x axis:1 unit = ₹ 200, y axis: 1 unit = ₹ 100
☛ Check: Class 10 Maths NCERT Solutions Chapter 3
Video Solution:
The coach of a cricket team buys 3 bats and 6 balls for ₹ 3900. Later, she buys another bat and 3 more balls of the same kind for ₹ 1300. Represent this situation algebraically and geometrically
NCERT Solutions Class 10 Maths Chapter 3 Exercise 1.1 Question 2
Summary:
The coach of a cricket team buys 3 bats and 6 balls for ₹ 3900. Later, she buys another bat and 3 more balls of the same kind for ₹ 1300. This situation is algebraically and geometrically represented.
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