The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is \(4{\Large\frac{2}{15}}\)cm. What is the length of either of the remaining equal sides?
Solution:
We know that,
In an isosceles triangle, two sides of the triangle are equal.
The perimeter of a triangle = Sum of the lengths of all three sides
Let's form a linear equation for the given problem statement.
Base of an isosceles triangle = 4/3 cm
Let the equal sides measure as x cm each
Therefore, Perimeter of the triangle = x + x + 4/3 = \(4{\Large\frac{2}{15}}\)
Solving the above equation
⇒ 2x + 4/3 = \(4{\Large\frac{2}{15}}\)
⇒ 2x = 62/15 - 4/3
⇒ 2x = 42/15
⇒ x = 21/15
⇒ x = 7/5
Therefore, the length of the remaining equal sides of the triangle is 7/5 cm
☛ Check: Class 8 Maths NCERT Solutions Chapter 2
Video Solution:
The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is \(4{\Large\frac{2}{15}}\) cm. What is the length of either of the remaining equal sides?
NCERT Solutions Class 8 Maths Chapter 2 Exercise 2.2 Question 3
Summary:
Given that the base of an isosceles triangle is 4/3 cm and its perimeter is \(4{\Large\frac{2}{15}}\)cm, the remaining equal sides are equal to 7/5 cm each.
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