The base of a parallelogram is (2x + 3 units) and the corresponding height is (2x - 3 units). Find the area of the parallelogram in terms of x. What will be the area of parallelogram of x = 30 units?

Solution:

Area of the parallelogram = Base × Height

Given, base of parallelogram = (2x + 3) units and

Height of parallelogram = (2x - 3) units

∴ Area of the parallelogram = Base × Height

= (2x + 3) × (2x - 3)

Using the standard identity: a² - b² = (a + b) (a - b)

= (2x)² - (3)²

= 4x² - 9

Given x = 30,

Area of the parallelogram = 4x² - 9

= 4(30)² - 9

= 3591 square units

✦ Try This: The base of a triangle is (5x - 3) units and the corresponding height is (5x + 3) units. Find the area of the triangle terms of x. What will be the area of triangle x = 10 units?

Given, the base of a triangle is (5x - 3) and the corresponding height is (5x + 3).

The area of the triangle = 1/2 × base × height

= 1/2 × (5x - 3) × (5x + 3)

= 1/2 [(5x)² - (3)²]

= 1/2 [25x² - 9]

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 106

The base of a parallelogram is (2x + 3 units) and the corresponding height is (2x - 3 units). Find the area of the parallelogram in terms of x. What will be the area of parallelogram of x = 30 units?

Summary:

The base of a parallelogram is (2x + 3) units and the corresponding height is (2x - 3) units. The area of the parallelogram in terms of x is 4x² - 9. The area of parallelogram of x = 30 units is 3591 square units.

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