The areas of any two faces of a cuboid are equal. Is the given statement true or false

Solution:

The statement is False.

The diagram below shows the six faces of the cuboid with length L, breadth B and height H.

It is evident from the above diagram that opposite sides of the cuboid are equal in area i.e.

Faces1 & 2; Faces 3 & 4; Faces 1 & 2; and Faces 5 & 6 are equal in areas.

✦ Try This: The surface area of a cuboid of Length L, breadth B and height H is 2(LH + BH + LB). Is the given statement true or false

Refer to the diagram below:

The surface area of the cuboid is given as:

Surface area of the cuboid = Sum of area of faces (1&2, 3&4, 5&6)

Area of faces 1&2 = 2(B × H)

Area of faces 3&4 = 2(L × B)

Area of faces 5&6 = 2(L × H)

Surface Area of the cuboid = 2(B × H) + 2(L × B) + 2(L × H) = 2[BH + LB + LH]

Hence the statement is true.

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 11

NCERT Exemplar Class 8 Maths Chapter 11 Problem 54

The areas of any two faces of a cuboid are equal. Is the given statement true or false

Summary:

The areas of any two faces of a cuboid are equal is a false statement

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