The area of a trapezium is 475 cm² and the height is 19 cm. Find the lengths of its two parallel sides if one side is 4 cm greater than the other.
Solution:
Given, area of a trapezium is 475 cm²
Height = 19 cm
We have to find the lengths of its two parallel sides if one side is 4 cm greater than the other.
Consider the trapezium ABCD
Let the side CD = x cm
Given, AB = x+4 cm
Area of trapezium = 1/2 × (sum of parallel sides) × distance between parallel sides
475 = 1/2 × (AB + CD) × 19
475 = 1/2 × (x + x + 4) × 19
475 × 2 = (2x + 4) × 19
2x + 4 = (475 × 2)/19
2x + 4 = 25 × 2
2x + 4 = 50
2x = 50 - 4
2x = 46
x = 23 cm
So, CD = 23 cm
AB = 23 + 4 = 27 cm
Therefore, the lengths of the parallel sides are 23 cm and 27 cm.
✦ Try This: The area of a trapezium is 755 cm² and the height is 15 cm. Find the lengths of its two parallel sides if one side is 7 cm greater than the other.
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 12
NCERT Exemplar Class 9 Maths Exercise 12.4 Problem 3
The area of a trapezium is 475 cm² and the height is 19 cm. Find the lengths of its two parallel sides if one side is 4 cm greater than the other.
Summary:
The area of a trapezium is 475 cm² and the height is 19 cm. The lengths of its two parallel sides if one side is 4 cm greater than the other are 23 cm and 27 cm
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