The amount of money in the account of Varun at the end of every year when Rs 1000 is deposited at simple interest of 10% per annum, do the lists of numbers involved form an AP

Solution:

An arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous term.

Simple Interest = Principal × rate × time/100.

From the question given,

Simple Interest = 1000× 10 × 1/100 = 100.

Hence, the amount of money in the account at end of every year is

1000, (1000 + 100 × 1), (1000 + 100 × 2), (1000 + 100 × 3),….. = 1000, 1100, 1200, 1300,….

Calculating the difference, we get,

d₁ = 1100 - 1000 = 100

d₂ = 1200 - 1100 = 100

d₃ = 1300 - 1200 = 100

Since, the d = 100 is the same for all, d₁ = d₂ = d₃, the given list of numbers forms an AP.

Therefore, it forms an A.P with a common difference 100

✦ Try This: The 13th term of an AP is four times its 3rd term. If its fifth term is 16, then find the sum of its first ten terms

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 5

NCERT Exemplar Class 10 Maths Exercise 5.2 Problem 7 (iii)

The amount of money in the account of Varun at the end of every year when Rs 1000 is deposited at simple interest of 10% per annum, do the lists of numbers involved form an AP

Summary:

The amount of money in the account of Varun at the end of every year when Rs 1000 is deposited at simple interest of 10% per annum forms an A.P

☛ Related Questions:

• The number of bacteria in a certain food item after each second, when they double in every second, d . . . .
• 2n - 3 is the nth term of an AP?
• 3n² + 5 is the nth term of an AP?