The 11th term of the AP: -5, -5 /2 , 0, 5/ 2 , ...is
a. -20
b. 20
c. -30
d. 30

Solution:

An arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous term.

The nth term of an AP is

aₙ = a + (n - 1 )d.

a = first term

aₙ = nth term

d = common difference.

Given in the question,

First term, a = - 5.

Common difference, d = -5/2 - (-5) = (-5 +10)/2 = 5/2

n = 11

Considering the question, we get,

aₙ = a + (n - 1 )d.

a₁₁ = - 5 + (11 - 1)(5/2)

a₁₁ = - 5 + (10)(5/2)

a₁₁ = - 5 + 25 = 20

a₁₁ = 20.

Therefore, a₁₁ = 20

✦ Try This: Find the 20th term for the given AP:3, 5, 7, 9, ……

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 5

NCERT Exemplar Class 10 Maths Exercise 5.1 Problem 4

The 11th term of the AP: -5, -5 /2 , 0, 5/ 2 , ...is, a. -20, b. 20, c. -30, d. 30

Summary:

An arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. The 11th term of the AP: -5, -5 /2 , 0, 5/ 2 , ...is 20

☛ Related Questions:

• The first four terms of an AP, whose first term is -2 and the common difference is -2, are, a. - 2, . . . .
• The 21st term of the AP whose first two terms are -3 and 4 is, a. 17, b. 137, c. 143, d. -143
• If the 2nd term of an AP is 13 and the 5th term is 25, what is its 7th term, a. 30, b. 33, c. 37, d. . . . .