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Sweety runs around a square park of side 75 m. Bulbul runs around a rectangular park with length 60 m and breadth 45 m. Who covers less distance?

Solution:

We will be using the formula for the perimeter of a square and the perimeter of a rectangle to calculate the distance covered by Sweety and Bulbul in the respective parks.

Sweety runs around a square park of side 75 m. Bulbul runs around a rectangular park with length 60 m and breadth 45 m. Who covers less distance?

Side of square park = 75 m

The perimeter of the square park = 4 × side

⇒ 4 × 75 = 300

Hence, Sweety covers 300 meters around the square park.

Now, the length of the rectangular park = 60 m

The breadth of the rectangular park = 45 m

The perimeter of rectangular park = 2 (Length + Breadth)

⇒ 2 (60 + 45)

⇒ 2 × 105 = 210

Hence, Bulbul covers 210 meters around the rectangular park.

Thus, we see that Bulbul covers a distance of 210 m which is lesser than the distance of 300 m covered by Sweety. Therefore, Bulbul covers a lesser distance.

NCERT Solutions for Class 6 Maths Chapter 10 Exercise 10.1 Question 15

Sweety runs around a square park of side 75 m. Bulbul runs around a rectangular park with length 60 m and breadth 45 m. Who covers less distance?

Summary:

It is given Sweety runs around a square park of side 75 m and Bulbul runs around a rectangular park with length 60 m and breadth 45 m. We see that Bulbul covers a distance of 210 m which is lesser than the distance of 300 m covered by Sweety. Therefore, Bulbul covers a lesser distance.

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