Subtract: 7p (3q + 7p) from 8p (2p - 7q)

Solution:

Given, subtract 7p (3q + 7p) from 8p (2p - 7q)

⇒ 8p (2p - 7q) - [7p (3q + 7p)]

= 16p² - 56pq - [21pq + 49p²]

= 16p² - 56pq - 21pq - 49p²

= 16p² - 49p² - 56pq - 21pq

= -33p² - 77pq

✦ Try This: Subtract: 3a(3b + 2a) from 5a(4a + 6b)

Given, subtract 3a(3b + 2a) from 5a(4a + 6b)

⇒ [5a(4a + 6b)] - [3a(3b + 2a)]

= (20a² + 30ab) - (9ab + 6a²)

= 20a² + 30ab - 9ab - 6a²

= 20a² - 6a² + 30ab - 9ab

= 14a² + 21ab

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 82(vi)

Subtract: 7p (3q + 7p) from 8p (2p - 7q)

Summary:

Subtracting 7p (3q + 7p) from 8p (2p - 7q) we get, -33p² - 77pq

☛ Related Questions:

• Subtract: -3p² + 3pq + 3px from 3p (-p - a - r)
• Multiply: -7pq²r³, -13p³q²r
• Multiply: 3x²y²z², 17xyz