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Subtract: 6x² - 4xy + 5y² from 8y² + 6xy - 3x²
Solution:
Given, subtract 6x² - 4xy + 5y² from 8y² + 6xy - 3x²
⇒ (8y² + 6xy - 3x²) - (6x² - 4xy + 5y²)
Grouping like terms,
= -3x² - 6x² + 6xy - (-4xy) + 8y² - 5y²
= -9x² + 10xy + 3y²
✦ Try This: Subtract: 7a² + 15ab - 3b² from 8a² - 25ab + 13b²
Given, (8a² - 25ab + 13b²) - (7a² + 15ab - 3b²)
= 8a² - 25ab + 13b² - 7a² - 15ab + 3b²
= 8a² - 7a² - 25ab - 15ab + 13b² + 3b²
= a² - 40ab + 16b²
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9
NCERT Exemplar Class 8 Maths Chapter 7 Problem 82(ii)
Subtract: 6x² - 4xy + 5y² from 8y² + 6xy - 3x²
Summary:
Subtracting 6x² - 4xy + 5y² from 8y² + 6xy - 3x² we get, - 9x² + 10xy + 3y²
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