Subtract: 2ab + 5bc - 7ac from 5ab - 2bc - 2ac + 10abc

Solution:

Given, subtract 2ab + 5bc - 7ac from 5ab - 2bc - 2ac + 10abc

⇒ 5ab - 2bc - 2ac + 10abc - (2ab + 5bc - 7ac)

= 5ab - 2ab - 2bc - 5bc - 2ac - (-7ac) + 10abc

= 3ab - 7bc + 5ac + 10abc

✦ Try This: Subtract: 3xy + 7yz - 8xz from 7xy - 9yz - 14xz + 15xyz

Given, 3xy + 7yz - 8xz from 7xy - 9yz - 14xz + 15xyz

⇒ (7xy - 9yz - 14xz + 15xyz) - (3xy + 7yz - 8xz)

= 7xy - 9yz - 14xz + 15xyz - 3xy - 7yz + 8xz

= 7xy - 3xy - 9yz - 7yz - 14xz + 8xz + 15xyz

= 4xy - 16yz - 6xz + 15xyz

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 82(v)

Subtract: 2ab + 5bc - 7ac from 5ab - 2bc - 2ac + 10abc

Summary:

Subtracting 2ab + 5bc - 7ac from 5ab - 2bc - 2ac + 10abc, we get, 3ab - 7bc + 5ac + 10abc

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