Subtract 2 (ab + bc + ca) from -ab - bc - ca

Solution:

Given, the expressions are 2 (ab + bc + ca) and -ab - bc - ca.

We have to subtract the expressions

2(ab + bc + ca) = 2ab + 2bc + 2ca

On subtracting the expressions,

= -ab - bc - ca - (2ab + 2bc + 2ca)

= -ab - bc - ca - 2ab - 2bc - 2ca

By combining the like terms,

= -ab - 2ab - bc - 2bc - ca - 2ca

By distributive property,

= (-1 - 2)ab + (-1 - 2)bc + (-1 - 2)ca

= (-3)ab + (-3)bc + (-3)ca

= -3ab - 3bc - 3ca

Therefore, the required expression is -3ab - 3bc - 3ca.

✦ Try This: Subtract 3(ab + bc + ca) from -2ab - 2bc - ca

☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 12

NCERT Exemplar Class 7 Maths Chapter 10 Problem 58 (h)

Subtract 2 (ab + bc + ca) from -ab - bc - ca

Summary:

On subtracting 2 (ab + bc + ca) from -ab - bc - ca, we get -3ab - 3bc - 3ca

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