Solve the following equations by trial and error method:
(i) 5p + 2 =17 (ii) 3m - 14 = 4

Solution:

According to the given question, we will use the trial and error method to solve the given equations.

(i) 5p + 2 =17.

5p + 2 = L.H.S

By putting, p = 0,

5(0) + 2 = 2 ≠ 17

By putting, p =1,

5(1) + 2 = 7 ≠ 17

By putting, p = 2,

5(2) + 2 = 12 ≠ R.H.S

By putting, p = 3,

5(3) + 2 = 17 = R.H.S

Therefore, p = 3 is a solution of the equation.

ii) 3m – 14 = 4

3m – 14 = L.H.S

By putting, m = 5,

3(5) – 14 = 1 ≠ 6

By putting, m = 6,

3(6) – 14 = 4 = R.H.S.

Therefore, m = 6 is a solution of the equation.

☛ Check: NCERT Solutions for Class 7 Maths Chapter 4

---

Video Solution:

Solve the following equations by trial and error method: (i) 5p + 2 =17 (ii) 3m - 14 = 4

NCERT Solutions for Class 7 Maths Chapter 4 Exercise 4.1 Question 3

Summary:

By using the trial and error method we have solved the following equations: (i) 5p + 2 = 17, p = 3 is a solution of the equation (ii) 3m - 14 = 4, m = 6 is a solution of the equation.

---

☛ Related Questions:

• Write Equations For The Following Statements Given I The Sum Of Numbers X And 4 Is 9 Ii 2 Subtracted From Y Is 8 Iii Ten Times A Is 70 Iv The Number B Divided By 5 Gives 6
• Write The Following Equations In Statement Forms I P 4 15 Ii M 7 3 Iii 2m 7 Iv M 5 3 V 3m 5 6 Vi 3p 4 25 Vii 4p 2 18 Viii P 2 2 8
• Set Up An Equation In The Following Cases I Irfan Says That He Has 7 Marbles More Than Five Times The Marbles Parmit Has Irfan Has 37 Marbles
• Complete The Last Column Of The Table