Solve the following equations.
(a) 4 = 5(p – 2) (b) – 4 = 5(p – 2) (c) 16 = 4 + 3(t + 2)
(d) 4 + 5(p – 1) = 34 (e) 0 = 16 + 4(m – 6)
Solution:
We use the concepts of simple linear equations and fundamental operations like addition, subtraction, multiplication and division to solve the problem.
(a) 4 = 5(p - 2)
4 = 5p - 10
5p = 4 + 10
Therefore, p = 14/5
(b) - 4 = 5(p - 2)
- 4 = 5p - 10
- 4 + 10 = 5p
6 = 5p
Therefore, p = 6/5
(c) 16 = 4 + 3(t + 2)
16 = 4 + 3t + 6
16 - 10 = 3t
6 = 3t
t = 6/3 = 2
(d) 4 + 5(p - 1) = 34
4 + 5p - 5 = 34
5p - 1 = 34
5p = 35
p = 35/5
p = 7
(e) 0 = 16 + 4(m - 6)
0 = 16 + 4m - 24
8 = 4m
m = 8/4
m = 2
☛ Check: NCERT Solutions for Class 7 Maths Chapter 4
Video Solution:
Solve the following equations. (a) 4 = 5(p – 2) (b) – 4 = 5(p – 2) (c) 16 = 4 + 3(t + 2) (d) 4 + 5(p – 1) = 34 (e) 0 = 16 + 4(m – 6)
NCERT Solutions for Class 7 Maths Chapter 4 Exercise 4.3 Question 3
Summary:
We have solved the following equations. (a) 4 = 5(p – 2); p = 14/5 (b) –4 = 5(p – 2; p = 6/5 ) (c) 16 = 4 + 3(t + 2); t = 2 (d) 4 + 5(p – 1) = 34 ; p = 7 (e) 0 = 16 + 4(m – 6); m = 2
☛ Related Questions:
- Solve The Following Equations A 2y 5 2 37 2 B 5t 28 10 C A 5 32 D Q 4 75 E 5 2 X 5 F 5 2 X 25 4
- Solve The Following Equations A 2x 4 12 B 3n 5 21 C 3n 5 21 D 4 2 X 8 E 42 X 8
- A Construct 3 Equations Starting With X 2 B Construct 3 Equations Starting With X 2
- Set Up Equations And Solve Them To Find The Unknown Numbers In The Following Cases A Add 4 To Eight Times A Number You Get 60 B One Fifth Of A Number Minus 4 Gives 3
visual curriculum