Solve : 4 (3p + 2) - 5(6p -1) = 2(p - 8) - 6(7p - 4)

Solution:

Given, the equation is 4 (3p + 2) - 5(6p -1) = 2(p - 8) - 6(7p - 4)

We have to solve the equation

On solving the equation for x,

4 (3p + 2) - 5(6p -1) = 2(p - 8) - 6(7p - 4)

4(3p) + 4(2) - 5(6p) + 5(1) = 2(p) - 2(8) - 6(7p) + 6(4)

12p + 8 - 30p + 5 = 2p - 16 - 42p + 24

12p - 30p + 8 + 5 = 2p - 42p - 16 + 24

p(12 - 30) + 13 = p(2 - 42) + 8

-18p + 13 = -40p + 8

By transposing,

-18p + 40p = 8 - 13

22p = -5

p = -5/22

Therefore, the value of p is -5/22

✦ Try This: Solve : 3(2p + 3) - 6(7p -7) = 3(p - 2) - 5(5p - 3)

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 2

NCERT Exemplar Class 8 Maths Chapter 4 Problem 76

Solve : 4 (3p + 2) - 5(6p -1) = 2(p - 8) - 6(7p - 4)

Summary:

On solving the equation 4 (3p + 2) - 5(6p -1) = 2(p - 8) - 6(7p - 4), we get p = -5/22

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