Solve : 1 -(x - 2) - [(x - 3) - (x - 1)] = 0

Solution:

Given, the equation is 1 -(x - 2) - [(x - 3) - (x - 1)] = 0

We have to solve the equation

On solving the equation for x,

1 -(x - 2) - [(x - 3) - (x - 1)] = 0

1 - x + 2 - x + 3 - x + 1 = 0

By grouping of common terms,

1 + 2 + 3 + 1 - x - x - x = 0

2 + 5 - 3x = 0

7 - 3x = 0

By transposing,

3x = 7

x = 7/3

Therefore, the value of x is 7/3

✦ Try This: Solve : 4 -(3x - 12) - [(x - 2) - (3x - 10)] = 0

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 2

NCERT Exemplar Class 8 Maths Chapter 4 Problem 66

Solve : 1 -(x - 2) - [(x - 3) - (x - 1)] = 0

Summary:

On solving the equation 1 -(x - 2) - [(x - 3) - (x - 1)] = 0, we get x = 7/3

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