Simplify: (pq - qr)² + 4pq²r

Solution: Given, (pq - qr)² + 4pq²r

Using standard identity: (a - b)² = a² - 2ab + b²

Here, a = pq and b = qr

(pq - qr)² + 4pq²r

= [(pq)² - 2pq²r + (qr)²] + 4pq²r

= (pq)² - 2pq²r + 4pq²r + (qr)²

= (pq)² + 2pq²r + (qr)²

✦ Try This: Simplify: (ab +bc)² - 4ab²c

Given, (ab + bc)² - 4ab²c

Using standard identity: (x + y)² = x² + 2xy + y²

(ab + bc)² - 4ab²c

= [(ab)² + 2ab²c + (bc)²] - 4ab²c

= a²b² + 2ab²c + b²c² - 4ab²c

= a²b² - 2ab²c + b²c²

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 84(xii)

Simplify: (pq - qr)² + 4pq²r

Summary:

Simplifying (pq - qr)² + 4pq²r we get, (pq)² + 2pq²r + (qr)²

☛ Related Questions:

• Simplify: (s²t + tq²)² - (2stq)²
• Expand using suitable identities: (xy + yz)²
• Expand using suitable identities: (x²y - xy²)²