Simplify: (49 × z⁻³) / (7⁻³ × 10 × z⁻⁵) where, z ≠ 0.

Solution:

Given, the expression is (49 × z⁻³) / (7⁻³ × 10 × z⁻⁵) where, z ≠ 0.

We have to simplify the given expression.

We know, 49 = 7²

Now, (49 × z⁻³) / (7⁻³ × 10 × z⁻⁵) = (7² × z⁻³) / (7⁻³ × 10 × z⁻⁵)

Using law of exponents,

am ÷ an = am - n

So, 72/7-3 = 72 + 3

= 75

Similarly, z-3/z-5 = z-3 + 5

= z2

Now, (49 × z-3) / (7-3 × 10 × z-5) = 75 × z2/10

Therefore, the required value is 75 × z2/10

✦ Try This: Simplify: (81 × z⁻⁴) / (9⁻³ × 12 × z⁻⁵) where, z ≠ 0

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 12

NCERT Exemplar Class 8 Maths Chapter 8 Problem 98(iii)

Simplify: (49 × z⁻³) / (7⁻³ × 10 × z⁻⁵) where, z ≠ 0.

Summary:

On simplifying (49 × z⁻³) / (7⁻³ × 10 × z⁻⁵) where, z ≠ 0 we get 7⁵ × z²/10 using the law of exponents

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