Sides of triangles are given below. Determine which of them are right triangles. In the case of a right triangle, write the length of its hypotenuse.
(i) 7 cm, 24 cm, 25 cm
(ii) 3 cm, 8 cm, 6 cm
(iii) 50 cm, 80 cm, 100 cm
(iv) 13 cm, 12 cm, 5 cm
Solution:
We know that in a triangle, if the square of one side is equal to the sum of the squares of the other two sides, then the angle opposite the first side is a right angle. (Pythagoras theorem)
(i) (25)2 = 625
72 + (24)2 = 49 + 576 = 625
Therefore, (25)2 = 72 + (24)2
It is a right triangle and length of hypotenuse = 25 cm [Since hypotenuse is the longest side of a right triangle]
(ii) 82 = 64
32 + 62 = 9 + 36 = 45
82 ≠ 32 + 62
Therefore, it's not a right triangle.
(iii) 1002 = 10000
502 + 802 = 2500 + 6400 = 8900
1002 ≠ 502 + 802
Therefore, it's not a right triangle.
(iv) 132 = 169
122 + 52 = 144 + 25 = 169
Therefore, 132 = 122 + 52
It is a right triangle and the length of the hypotenuse = 13cm
Thus (i) and (iv) are right triangles.
☛ Check: NCERT Solutions Class 10 Maths Chapter 6
Video Solution:
Sides of triangles are given below. Determine which of them are right triangles. In the case of a right triangle, write the length of its hypotenuse. (i) 7 cm, 24 cm, 25 cm (ii) 3 cm, 8 cm, 6 cm (iii) 50 cm, 80 cm, 100 cm (iv) 13 cm, 12 cm, 5 cm
NCERT Class 10 Maths Solutions Chapter 6 Exercise 6.5 Question 1
Summary:
Sides of triangles are given below. We have, (i) 7 cm, 24 cm, 25 cm: Right-angled triangle with 25 cm as hypotenuse (ii) 3 cm, 8 cm, 6 cm: Not a right-angled triangle. (iii) 50 cm, 80 cm, 100 cm: Not a right-angled triangle. (iv) 13 cm, 12 cm, 5 cm: Right-angled triangle with 13 cm as hypotenuse.
☛ Related Questions:
- PQR is a triangle right angled at P and M is a point on QR such that PM ⊥ QR. Show that (PM)^2 = QM.MR
- In Fig. 6.53, ABD is a triangle right angled at A and AC ⊥ BD. Show that (i) AB² = BC.BD (ii) AC² = BC.DC (iii) AD² = BD.CD.
- ABC is an isosceles triangle right angled at C. Prove that AB^2 = 2AC^2.
- ABC is an isosceles triangle with AC = BC. If AB^2 = 2AC^2, prove that ABC is a right triangle.
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