Show that the points A (1, 2), B (-1, -16) and C (0, -7) lie on the graph of the linear equation y = 9x - 7
Solution:
Given, the points are A(1, 2), B(-1, -16) and C(0, -7)
The linear equation is y = 9x - 7
We have to show that the given points lie on the graph of the linear equation.
When x = 2,
y = 9(2) - 7
y = 18 - 7
y = 11
When x = -2,
y = 9(-2) - 7
y = -18 - 7
y = -25
Therefore, the points are (2, 11) and (-2, -25)
On plotting the points on the graph and joining them, we obtain a straight line
The graph of the equation is a straight line.
We observe that the points A, B and C lie on the straight line.
✦ Try This: The value of k for which the pair of equations 3x + 4y + 2 = 0 and 9x + 12y + k = 0 represent coincident lines is
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 4
NCERT Exemplar Class 9 Maths Exercise 4.4 Problem 1
Show that the points A (1, 2), B (-1, -16) and C (0, -7) lie on the graph of the linear equation y = 9x - 7
Summary:
It is shown that the points A (1, 2), B (- 1, - 16) and C (0, - 7) lie on the graph of the linear equation y = 9x - 7. From the graph mentioned above, we observe that the points A, B and C lie on the straight line DE
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