Saili plants 4 saplings, in a row, in her garden. The distance between two adjacent saplings is 3/4 m. Find the distance between the first and the last sapling

Solution:

Total number of saplings = 4

Distance between two adjacent saplings = 3/4 m

Distance between the first and the last sapling = 3 × 3/4 m = 9/4 m

By converting an improper fraction into a mixed fraction, we get

9/4 m = \(2{\Large\frac{1}{4}}\) m

Thus, the distance between the first and last sapling is \(2{\Large\frac{1}{4}}\) m.

☛ Check: NCERT Solutions for Class 7 Maths Chapter 2

Video Solution:

Saili plants 4 saplings, in a row, in her garden. The distance between two adjacent saplings is 3/4 m. Find the distance between the first and the last sapling

NCERT Solutions Class 7 Maths Chapter 2 Exercise 2.3 Question 5:

Summary:

Saili plants 4 saplings, in a row, in her garden. The distance between two adjacent saplings is 3/4 m. The distance between the first and last sapling is \(2{\Large\frac{1}{4}}\) m.

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