Product of the following monomials 4p, - 7q³, -7pq is
(a) 196 p²q⁴
(b) 196 pq⁴
(c) -196 p²q⁴
(d) 196 p²q³
Solution:
Correct answer is option (a).because
Given, product of the monomials 4p, -7q³, -7pq
4p × (-7q³) × (-7pq)
= [4 × (-7) × (-7)] × [p × q³ × 7pq]
= 196 p²q⁴
✦ Try This: The product of 7xy, 2x²y and 7xy² is ____?
The product of 7xy, 2x²y and 7xy²
⇒ 7xy × 2x²y × 7xy²
= 98x⁴y⁴
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9
NCERT Exemplar Class 8 Maths Chapter 7 Problem 9
Product of the following monomials 4p, - 7q³, -7pq is (a) 196 p²q⁴, (b) 196 pq⁴, (c) - 196 p²q⁴, (d) 196 p²q³
Summary:
Product of the following monomials 4p, - 7q³, -7pq is 196 p²q⁴
☛ Related Questions:
- Area of a rectangle with length 4ab and breadth 6b² is (a) 24a²b² (b) 24ab³ (c) 24ab² (d) 24ab
- Volume of a rectangular box (cuboid) with length = 2ab, breadth = 3ac and height = 2ac is (a) 12a³bc . . . .
- Product of 6a² – 7b + 5ab and 2ab is (a) 12a³b – 14ab² + 10ab (b) 12a³b – 14ab² + 10a²b² (c) 6a² – 7 . . . .
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