Product of 6a² - 7b + 5ab and 2ab is
(a) 12a³b - 14ab² + 10ab
(b) 12a³b - 14ab² + 10a²b²
(c) 6a² - 7b + 7ab
(d) 12a²b - 7ab² + 10ab

Solution:

Correct answer is option (b).

Given, (6a² - 7b + 5ab) × 2ab

Multiplying each term by 2ab

= (6a² × 2ab) - (7b × 2ab) + (5ab × 2ab)

= 12a³b - 14ab² + 10a²b²

✦ Try This: Product of (2x² + 5y + 6xy²) and 2xy is ________?

Product of (2x² + 5y + 6xy²) and 2xy

= (2x² + 5y + 6xy²) × 2xy

= 4x³y + 10xy² + 12x²y³

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

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NCERT Exemplar Class 8 Maths Chapter 7 Problem 12

Product of 6a² - 7b + 5ab and 2ab is (a) 12a³b - 14ab² + 10ab, (b) 12a³b - 14ab² + 10a²b², (c) 6a² - 7b + 7ab, (d) 12a²b - 7ab² + 10ab

Summary:

Product of 6a² - 7b + 5ab and 2ab is 12a³b - 14ab² + 10a²b²

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