One of the zeroes of the polynomial 2x² + 7x -4 is
a. 2
b. 1/2
c. -1/2
d. -2

Solution:

We know that

Zero of the polynomial p(x) = 0

It is given that

p(x) = 2x² + 7x -4

So we get

2x² + 7x -4 = 0

By splitting the middle term

2x (x + 4) - 1 (x + 4) = 0

(x + 4) (2x - 1) = 0

We get

x = -4 and x = 1/2

Therefore, one of the zeroes is 1/2.

✦ Try This: One of the zeroes of the polynomial 3x² + 6x - 4 is

We know that

Zero of the polynomial p(x) = 0

It is given that

p(x) = 3x² + 6x - 4

So we get

3x² + 12x - 12 = 0

By splitting the middle term

3x² + 6x + 6x - 12 = 0

3x (x + 2) - 6 (x + 2) = 0

(x + 2) (3x - 6) = 0

We get

x = -2 and x = 1/2

Therefore, the zeroes of the polynomial are -2 and 1/2.

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2

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NCERT Exemplar Class 9 Maths Exercise 2.1 Problem 10

One of the zeroes of the polynomial 2x² + 7x -4 is a. 2, b. 1/2, c. -1/2, d. -2

Summary:

The zeros of a polynomial are the values of x which satisfy the equation y = f(x). One of the zeroes of the polynomial 2x² + 7x -4 is 1/2

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☛ Related Questions:

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