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Observe the following nutritional chart carefully:
Food Item (Per Unit = 100g) Carbohydrates
Rajma 60g
Cabbage 5g
Potato 22g
Carrot 11g
Tomato 4g
Apples 14g
Write an algebraic expression for the amount of carbohydrates in ‘g’ for y units of potatoes and 2 units of rajma

Solution:

The given chart represents the amount of carbohydrates of each food.

We have to write an algebraic expression for the amount of carbohydrates in ‘g’ for y units of potatoes and 2 units of rajma.

From the table,

One unit of potato contains 22g of carbohydrates

So, y units of potato contains (22×y)g of carbohydrates

Carbohydrates in y units of potato = 22y g

One unit of Rajma contains 60 g of carbohydrates

So, 2 units of Rajma contains (2×60)g of carbohydrates

Carbohydrates in 2 units of Rajma = 120 g

Algebraic expression for y units of potatoes and 2 units of rajma = 22y + 120

Therefore, the required expression is 22y + 120.

✦ Try This: If A = x² + x + 1, B = 4x² - 3x + 2 and C = x² - 4x + 6, then find A - B + C

☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 12

NCERT Exemplar Class 7 Maths Chapter 10 Problem 73 (a)

Observe the following nutritional chart carefully, Write an algebraic expression for the amount of carbohydrates in ‘g’ for y units of potatoes and 2 units of rajma

Summary:

An algebraic expression for the amount of carbohydrates in ‘g’ for y units of potatoes and 2 units of rajma is 22y + 120

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