Multiply: (ab + c), (ab + c)

Solution:

Given, multiply (ab + c), (ab + c)

⇒ (ab + c) × (ab + c) = (ab + c)²

Using the standard identity: (a + b)² = a² + 2ab + c²

= (ab)² + 2(ab)(c) + c²

= (ab)² + 2abc + c²

✦ Try This: Multiply: (pq + rs), (pq + rs)

Given, Multiply: (pq + rs), (pq + rs)

⇒(pq + rs) × (pq + rs)

=(pq)² + pqrs + pqrs + (rs)²

=(pq)² + 2pqrs+ (rs)²

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 83(xvi)

Multiply: (ab + c), (ab + c)

Summary:

Multiplying (ab + c), (ab + c) we get, (ab)² + 2abc + c²

☛ Related Questions:

• Multiply: (pq - 2r), (pq - 2r)
• Multiply: [(3/4)x - (4/3)y], [(2/3)x + (3/2)y]
• Multiply: (3/2)p² + (2/3)q² , (2p² - 3q²)