Multiply: (a² - b²), (a² + b²)

Solution:

Given, multiply (a² - b²), (a² + b²)

Using the standard identity (x + y)(x - y) =x² - y²

Here, x = a² and y = b²

⇒ (a² - b²) × (a² + b²)

= [(a²)² - (b²)²]

= a⁴ - b⁴

✦ Try This: Multiply: (p³ - q³), (p³ + q³)

Given, Multiply: (p³ - q³), (p³ + q³)

Using the standard identity (x + y)(x - y) =x² - y²

Here, x = p³ and y = q³

⇒(p³ - q³) x (p³ + q³)

= [(p³)]² - [(q³)]² = p⁶ - q⁶

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 83(xv)

Multiply: (a² - b²), (a² + b²)

Summary:

Multiplying (a² - b²), (a² + b²) we get, a⁴ - b⁴

☛ Related Questions:

• Multiply: (ab + c), (ab + c)
• Multiply: (pq - 2r), (pq - 2r)
• Multiply: [(3/4)x - (4/3)y], [(2/3)x + (3/2)y]