Multiply: (3/2)p² + (2/3)q² , (2p² - 3q²)

Solution:

Given, multiply (3/2)p² + 2/3q² , (2p² -3q²)

⇒ [(3/2)p² + 2/3q²] × (2p² -3q²)

= 3p⁴ - (9/2)p²q² + 4/3p²q² - 2q²

✦ Try This: Multiply: (5/4)a² + (2/3)b² , (4a² -3b²)

Given, Multiply: (5/4)a² + (2/3)b² , (4a² -3b²)

⇒ [(5/4)a² + (2/3)b²] × [(4a² -3b²)]

=5a⁴ - (15/4)a²b² + (8/3)a²b² - 2b⁴

=5a⁴ - (13/12)a²b² - 2b⁴

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 83(xix)

Multiply: (3/2)p² + (2/3)q² , (2p² - 3q²)

Summary:

Multiplying (3/2)p² + 2/3q² , (2p² -3q²), We get 3p⁴ - (9/2)p²q² + 4/3p²q² - 2q²

☛ Related Questions:

• Multiply: (x² - 5x + 6), (2x + 7)
• Multiply: (3x² + 4x - 8), (2x² - 4x + 3)
• Multiply: (2x - 2y - 3), (x + y + 5)