Match the following:
(i) 425 × 136 = 425 × (6 + 30 + 100) (a) Commutativity under multiplication.
(ii) 2 × 49 × 50 = 2 × 50 × 49 (b) Commutativity under addition.
(iii) 80 + 2005 + 20 = 80 + 20 + 2005 (c) Distributivity of multiplication over addition.
Solution:
(i) 425 × 136 = 425 × (6 + 30 + 100)
This expression is simplified using the property of distributivity of multiplication over addition.
According to the distributive property of multiplication over addition,
a × (b + c) = a × b + a × c
425 × 136 = 425 × (6 + 30 + 100)
= 425 × 6 + 425 × 30 + 425 × 100
Hence (c) distributivity of multiplication over addition is the correct answer.
(ii) 2 × 49 × 50 = 2 × 50 × 49
This expression will be simplified by using the property of commutativity under multiplication
According to the commutative property over multiplication,
a × b = b × a
or a × b × c = a × c × b
2 × 49 × 50 = 2 × 50 × 49
Hence, (a) commutativity under multiplication is the correct answer
(iii) 80 + 2005 + 20 = 80 + 20 + 2005
This expression will be simplified by using the property of commutativity under the addition.
According to the commutative property over addition,
a + b = b + a
or a + b + c = a + c + b
80 + 2005 + 20 = 80 + 20 + 2005
Hence, (b) commutativity under addition is the correct answer
NCERT Solutions for Class 6 Maths Chapter 2 Exercise 2.2 Question 7
Match the following: (i) 425 × 136 = 425 × (6 + 30 + 100) (a) Commutativity under multiplication (ii) 2 × 49 × 50 = 2 × 50 × 49 (b) Commutativity under addition (iii) 80 + 2005 + 20 = 80 + 20 + 2005 (c) Distributivity of multiplication over addition
Summary:
(i) 425 × 136 = 425 × (6+ 30 + 100) matches with (c) Distributivity of multiplication over addition. (ii) 2 × 49 × 50 = 2 × 50 × 49 matches with (a) Commutativity under multiplication. (iii) 80 + 2005 + 20 = 80 + 20 + 2005 matches with (b) Commutativity under addition
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