Locate √13 on the number line

Solution:

We have to locate √13 on the number line.

Expressing 13 as a sum of two perfect square numbers.

13 = (2)² + (3)²

4 + 9 = 13

Lets draw the number line

Consider OA = 3 units

Now draw BA perpendicular to OA

Let BA = 2 units

Now join OB.

Using a compass with centre O and radius OB drawn an arc that intersects the number line at the point P.

Now, P = √13

By pythagoras theorem,

OB² = OA² + AB²

OB² = (3)² + (2)²

OB² = 9 + 4

OB² = 13

Taking square root,

Therefore, OB = √13

✦ Try This: Locate √14 on the number line.

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 1

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NCERT Exemplar Class 9 Maths Exercise 1.3 Sample Problem 1

Locate √13 on the number line

Summary:

A number line is a visual representation of numbers on a straight line. The point P on the number line represents √13

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