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Let E = 3, B = 7 and A = 4. Find the other digits in the sum
B A S E
+B A L L
G AM E S

Solution:

Since E = 3, B = 7 and A = 4 we can write

74 S 3

+7 4 L L

G4 M 3 S

3 + L = S

S + L = 3

L can assume the value of 5 because

3 + 5 = 8 = S

S = 8

8 + 5 = 13 (one carry over)

M = 4 + 4 + 1(from Carry over)

M = 9

G = 1 from the carry over of 7 + 7 = 14=

L = 5; S = 8; M = 9; G = 1

✦ Try This: Find the other digits in the sum

4 A B

+B A 4

1 C 1 0

B + 4 = number ending with 0

Therefore

B = 6

1 + A + A = number ending with 1

That is possible if A = 5

1 + 5 + 5 = 11 (number ending with 1)

4 + B + 1 = D

B = 6

4 + 6 + 1 = 11( and one carries over)

4 5 6

+6 5 4

1 1 1 0

A = 5; B = 6 and C = 1

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 16

NCERT Exemplar Class 8 Maths Chapter 13 Problem 67

Let E = 3, B = 7 and A = 4. Find the other digits in the sum B A S E + B A L L = G AM E S

Summary:

The other digits are as follows L = 5, S = 8, M = 9, G = 1

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