Let abc be a three-digit number. Then abc - cba is not divisible by
(a) 9
(b) 11
(c) 18
(d) 33
Solution:
abc = a × 10² + b × 10¹ + c × 10⁰
cba = c × 10² + b × 10¹ + a × 10⁰
Therefore
abc - cba = (100 - 1)a - (1 - 100)c = 99a - 99c = 99(a - c)
Therefore abc - cba is not divisible by 18
The correct choice is (c ).
✦ Try This: Let ab be a two-digit number. Then ab - ba is divisible by (a) 9, (b) 11, (c) 18, (d) 33
ab = a × 10¹ + b × 10⁰ = 10a + b
ba = b × 10¹ + a × 10⁰ = 10b + a
ab - ba = 10a + b - 10b - a = 9a - 9b = 9(a - b)
Therefore we can state that ab - ba = 9(a-b) and
It is divisible by 9.
The correct choice is (a).
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 16
NCERT Exemplar Class 8 Maths Chapter 13 Problem 4
Let abc be a three-digit number. Then abc - cba is not divisible by (a) 9, (b) 11, (c) 18, (d) 33
Summary:
Let abc be a three-digit number. Then abc - cba is not divisible by 18.
☛ Related Questions:
- The sum of all the numbers formed by the digits x, y and z of the number xyz is divisible by (a) 11, . . . .
- A four-digit number aabb is divisible by 55. Then possible value(s) of b is/are (a) 0 and 2, (b) 2 a . . . .
- Let abc be a three digit number. Then abc + bca + cab is not divisible by (a) a + b + c, (b) 3, (c) . . . .
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