It is given that △ABC ~ △PQR, with BC/QR = 1/3. Then ar(PRQ)/ar(BCA) is equal to
a. 9
b. 3
c. 1/3
d. 1/9

Solution:

Given, the triangles ABC and PQR are similar.

BC/QR = 1/3

We have to find the ratio of the area of the triangles PQR and BCA.

We know that the ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides.

So, area of PQR/area of BCA = QR²/BC²

= (3)²/1

= 9/1

Therefore, ar(PRQ)/ar(BCA) = 9

✦ Try This: It is given that △ABC ~ △PQR, with BC/QR = 2/3. Then ar(PRQ)/ar(BCA) is equal to

Given, the triangles ABC and PQR are similar.

BC/QR = 2/3

We have to find the ratio of the area of the triangles PQR and BCA.

We know that the ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides.

So, area of PQR/area of BCA = QR²/BC²

= (3)²/(2)²

= 9/4

Therefore, ar(PRQ)/ar(BCA) = 9/4

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 6

NCERT Exemplar Class 10 Maths Exercise 6.1 Problem 8

It is given that △ABC ~ △PQR, with BC/QR = 1/3. Then ar(PRQ)/ar(BCA) is equal to, a. 9, b. 3, c. 1/3, d. 1/9

Summary:

It is given that △ABC ~ △PQR, with BC/QR = 1/3. Then ar(PRQ)/ar(BCA) is equal to 9

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