Insert a rational number and an irrational number between 3.623623 and 0.484848
Solution:
Given, the numbers are 3.623623 and 0.484848.
Rational numbers are numbers which are in the form of p/q, where q is not equal to 0, p and q are integers.
Irrational numbers are numbers which are in decimal form.
To find a rational number R, we use the formula,
R = (p + q)/2
Let p = 3.623623 and q = 0.484848, we get,
R = (3.623623 + 0.484848)/2
R = (4.108471)/2
R = 2.0542355.
To find an irrational number Q, we use the formula,
Q = √pq,
where p and q are not perfect squares.
Q = √3.623623(0.484848)
Q = 1.3254834455….
Therefore, the rational number is 2.0542355 and the irrational number is 1.3254834455
✦ Try This: Insert a rational number and an irrational number between 2.676767 and 3.090909.
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 1
NCERT Exemplar Class 9 Maths Exercise 1.3 Problem 3(ix)
Insert a rational number and an irrational number between 3.623623 and 0.484848
Summary:
The rational number and irrational number between 3.623623 and 0.484848 are 2.0542355 and 1.3254834455… respectively
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