In ∆ PQR, if ∠R > ∠Q, then
a. QR > PR
b. PQ > PR
c. PQ < PR
d. QR < PR

Solution:

Consider the ∆ PQR

It is given that

∠R > ∠Q

As the sides opposite to greater angle is greater

PQ > PR

Therefore, PQ > PR.

✦ Try This: In ∆ ABC, if ∠C > ∠B, then a. BC > AC, b. AB > AC, c. AB < AC, d. BC < AC

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 7

NCERT Exemplar Class 9 Maths Exercise 7.1 Problem 9

In ∆ PQR, if ∠R > ∠Q, then , a. QR > PR , b. PQ > PR , c. PQ < PR , d. QR < PR

Summary:

A triangle is a closed shape with 3 angles, 3 sides, and 3 vertices. In ∆ PQR, if ∠R > ∠Q, then PQ > PR

☛ Related Questions:

• In triangles ABC and PQR, AB = AC, ∠C = ∠P and ∠B = ∠Q. The two triangles are ,a. isosceles but not . . . .
• In triangles ABC and DEF, AB = FD and ∠A = ∠D. The two triangles will be congruent by SAS axiom if , . . . .
• In the two triangles ABC and DEF, AB = DE and AC = EF. Name two angles from the two triangles that m . . . .