In ∆ PQR, ∠R = ∠P and QR = 4 cm and PR = 5 cm. Then the length of PQ is
a. 4 cm
b. 5 cm
c. 2 cm
d. 2.5 cm

Solution:

It is given that

In ∆ PQR, ∠R = ∠P

QR = 4 cm

PR = 5 cm

Here ∠R = ∠P then ∆ PQR is an isosceles triangle

We know that

PQ = QR

So PQ = 4 cm

Therefore, the length of PQ is 4 cm.

✦ Try This: In ∆ ABC, ∠C = ∠A and BC = 2 cm and AC = 3 cm. Then the length of AB is a. 2 cm, b. 3 cm, c. 4 cm, d. 4.5 cm

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 7

NCERT Exemplar Class 9 Maths Exercise 7.1 Problem 5

In ∆ PQR, ∠R = ∠P and QR = 4 cm and PR = 5 cm. Then the length of PQ is a. 4 cm, b. 5 cm, c. 2 cm, d. 2.5 cm

Summary:

In ∆ PQR, ∠R = ∠P and QR = 4 cm and PR = 5 cm. Then the length of PQ is 4 cm

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