In Fig. 9.44, a rectangle with perimeter 264 cm is divided into five congruent rectangles. Find the perimeter of one of the rectangles.
Solution:
Given, the perimeter of a rectangle is 264 cm
The rectangle is divided into five congruent rectangles
We have to find the perimeter of one of the rectangles.
Let the length be l and breadth be b
Perimeter of rectangle = 2(length + breadth)
From the figure,
Perimeter of rectangle = l + b + l + l + b + l + b + b + b
= 4l + 5b
Given, 264 = 4l + 5b ------------- (1)
According to the figure,
We observe that 2l = 3b ------------ (2)
Substituting (2) in (1),
264 = 2(3b) + 5b
264 = 6b + 5b
11b = 264
b = 264/11
b = 24 cm
Now, 2l = 3(24)
l = 3(24)/2
l = 3(12)
l = 36 cm
Perimeter of one rectangle = 2(36 + 24)
= 2(60)
= 120 cm
Therefore, the perimeter of one rectangle is 120 cm.
✦ Try This: How many different rectangles can be made with a 86 cm long string? Find the possible pairs of length and breadth of the rectangles.
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 11
NCERT Exemplar Class 7 Maths Chapter 9 Problem 91
In Fig. 9.44, a rectangle with perimeter 264 cm is divided into five congruent rectangles. Find the perimeter of one of the rectangles.
Summary:
In Fig. 9.44, a rectangle with perimeter 264 cm is divided into five congruent rectangles. The perimeter of one of the rectangles is 120 cm.
☛ Related Questions: