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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
In Fig. 9.4, the area of parallelogram ABCD is :
a. AB × BM
b. BC × BN
c. DC × DL
d. AD × DL
Solution:
We know that
Area of a parallelogram is the product of any side and its corresponding altitude
If AB is the base and DL is the height
Area of parallelogram = AB × DL
If AD is the base and BM is the height
Area of parallelogram = AD × BM
If DC is the base and DL is the height
Area of parallelogram = DC × DL
Therefore, the area of parallelogram is DC × DL.
✦ Try This: The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 6 cm and 4 cm is :
NCERT Exemplar Class 9 Maths Exercise 9.1 Problem 4
In Fig. 9.4, the area of parallelogram ABCD is : a. AB × BM, b. BC × BN, c. DC × DL, d. AD × DL
Summary:
A parallelogram is a special kind of quadrilateral that is formed by parallel lines. In Fig. 9.4, the area of parallelogram ABCD is DC × DL
☛ Related Questions:
- In Fig. 9.5, if parallelogram ABCD and rectangle ABEF are of equal area, then : a. Perimeter of ABCD . . . .
- The mid-point of the sides of a triangle along with any of the vertices as the fourth point make a p . . . .
- Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is a. . . . .
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