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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
In Fig. 6.2, POQ is a line. The value of x is
a) 20°
b) 25°
c) 30°
d) 35°
Solution:
Given, POQ is a line.
We have to find the value of x.
We know that if a ray stands on a line, then the adjacent angles so formed are supplementary.
Let the two rays initiating from the point O be OA and OB.
So, ∠POA + ∠AOB + ∠BOQ = 180°
40° + 4x + 3x = 180°
4x + 3x = 180° - 40°
7x = 140°
x = 140°/7
x = 20°
Therefore, the value of x is 20°
✦ Try This: Can an acute angle be adjacent to an obtuse angle?
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 6
NCERT Exemplar Class 9 Maths Exercise 6.1 Problem 6
In Fig. 6.2, POQ is a line. The value of x is, a) 20°, b) 25°, c) 30°, d) 35°
Summary:
The figure represents two rays initiating from the point O. POQ form a linear pair of angles.In Fig. 6.2, POQ is a line. The value of x is 20°
☛ Related Questions:
- In Fig. 6.3, if OP||RS, ∠OPQ = 110° and ∠QRS = 130°, then ∠PQR is equal to a) 40°, b) 50°, c) 60°, d . . . .
- Angles of a triangle are in the ratio 2 : 4 : 3. The smallest angle of the triangle is a) 60°, b) 40 . . . .
- Let OA, OB, OC and OD are rays in the anticlockwise direction such that ∠ AOB = ∠COD = 100°, ∠BOC = . . . .
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