In Fig. 5.9, PQ is a mirror, AB is the incident ray and BC is the reflected ray. If ∠ ABC = 46°, then ∠ ABP is equal to
a. 44°
b. 67°
c. 13°
d. 62°
Solution:
Given, PQ is a mirror
AB is the incident ray
BC is the reflected ray
∠ABC = 46°
We have to find the measure of ∠ ABP.
We know that the angle of incidence is equal to the angle of reflection
∠ABP = ∠CBQ --------------------------- (1)
We know that the linear pair of angles is always equal to 180 degrees.
So, ∠ABP + ∠ABC + ∠CBQ = 180°
From (1),
∠ABP + 46° + ∠ABP = 180°
2∠ABP + 46° = 180°
2∠ABP = 180° - 46°
2∠ABP = 134°
∠ABP = 134°/2
Therefore, ∠ABP = 67°
✦ Try This: In figure, OA and OB are opposite rays if y = 35°, what is the value of x?
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 5
NCERT Exemplar Class 7 Maths Chapter 5 Problem 3
In Fig. 5.9, PQ is a mirror, AB is the incident ray and BC is the reflected ray. If ∠ ABC = 46°, then ∠ ABP is equal to: a. 44°, b. 67°, c. 13°, d. 62°
Summary:
In Fig. 5.9, PQ is a mirror, AB is the incident ray and BC is the reflected ray. If ∠ ABC = 46°, then ∠ ABP is equal to 67°
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